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WAEC 2013 GCE Alternative to Chemistry Practical Question and Answers

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(1a) Va=22.50cm3,
mass conc. Of acid(Ca)=mass conc/molar mass,

molar mass NaHSO4=23+1+32+64=120g/mol ,

molar conc Ca=10.6/120=0.0883mol/dm3

(1aii)Cb=(0.0883*22.50)/25=0.0795mol/dm3 
(1aiii)mass conc. Cb=0.0795*40=3.178g/dm3,
X=3.178g/dm3

(1aiv) n=C*V/1000,
n of Na2SO4=mass/molar mass,
nb=(0.0795*25)/1000=0.0019875,
mass of NaSO4=n*molar mass,mass of Na2SO4=142g/mol,
mass of Na2SO4=0.0019875*142=0.282g.

(1bi) Phenopthalein
1bii)  (I.)

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